[tex]\frac{1}{2^{x} } =\frac{4^{x} }{8} \\2^{-x} =\frac{2^{2x} }{2^{3} } \\2^{-x} =2^{2x-3} \\-x=2x-3\\-x-2x=-3\\-3x=-3\\x=1[/tex]
Raspuns:
n=1
Rezolvare
Facem produsele in diagonala:
8=2ⁿ×4ⁿ. Am folosit n in loc de x...
4=2² iar 8=2³
Deci
2³=2ⁿ×(2²)ⁿ=2ⁿ×2²ⁿ=2³ⁿ
Inseamna ca 3=3n, sau n=1
