ms = 50g, w% = 3,65%
w% = mdx100/ms
=> ms = mdx100/w% = 50x3,65/100 = 1,825g HCl
M.NaHCO3 = 23+1+12+3x16 = 84 g/mol
M.HCl = 1+35,5 = 36,5 g/mol
m g 1,825g
NaHCO3 + HCl --> NaCl + H2O + CO2
84 36,5
=> m = 84x1,825/36,5 = 4,2 g soda alimentara
