V.alcool = 300 mL , p= 0,78 g/ml
p = m/V => m = pxV = 300x,078 = 234 g
w% = mdx100/ms => md = msxw%/100 = 234x96/100
= 224,64 g alcool
224,64 g V L
C2H5OH --H+--> C2H4 + H2O
46 22,4
=> V = 224,64x22,4/46 = 109,4 L etena obtinut la 100%
109,4 L .................... 100%
V L .......................... 90%
= 98,45 L
