Răspuns:
Explicație pas cu pas:
a) x²+x-2 = x²+2x-x-2 = x(x+2)-(x+2) = (x+2)(x-1)
b) x²-x-2 = x²-2x+x-2 = x(x-2)+(x-2) = (x-2)(x+1)
c) x²-2x-3 = x²-3x+x-3 = x(x-3)+(x-3) = (x-3)(x+1)
d) x²+2x-3 = x²+3x-x-3 = x(x+3)-(x+3) = (x+3)(x-1)
e) x²+x-6 = x²+3x-2x-6 = x(x+3)-2(x+3) = (x+3)(x-2)
f) x²-x-6 = x²-3x+2x-6 = x(x-3)+2(x-3) = (x-3)(x+2)
