Răspuns :
((a×2-155)×2-200)×2-250=50
((a×2-155)×2-200)×2=250+50=300
(a×2-155)×2-200=300:2=150
(a×2-155)×2=150+200=350
a×2-155=350:2=175
a×2=175+155=330
a=330:2=165
Da este vorba despre metoda mersului invers.
((a×2-155)×2-200)×2-250=50
((a×2-155)×2-200)×2=250+50=300
(a×2-155)×2-200=300:2=150
(a×2-155)×2=150+200=350
a×2-155=350:2=175
a×2=175+155=330
a=330:2=165
Da este vorba despre metoda mersului invers.