Răspuns:
Explicație pas cu pas:
La numarator trecem in baza 2:
log(2;4) = log(2;2^2) = 2, log(2;16) =log(2;2^4) =4
log(2;x) +log(2;x)/2 + log(2;x)/4 = 7/4*log(2;x)
La numitor trecem in baza 5:
log5;25) = 2, log(5;0,2) = log(5;1/5) = -1
log(5;x) +log(5;x)/2 +log(5;x)/(-1) = log(5;x)
B = ( 7/4*log(2;x))/log(5;x)
