Răspuns :
[tex]\it i) \ \ = 5^{4+5-3-2+6-10}=5^0=1\\ \\ \\ ii)\ \ =7^{8-6}-6^{3+5-6}+5^2+4^2-6\cdot3^2=49-36+25+16-54=\\ \\ =90-90=0[/tex]
[tex]\it i) \ \ = 5^{4+5-3-2+6-10}=5^0=1\\ \\ \\ ii)\ \ =7^{8-6}-6^{3+5-6}+5^2+4^2-6\cdot3^2=49-36+25+16-54=\\ \\ =90-90=0[/tex]