A) [(3a +19): 5-2] ×11 + 2 = 35
11(3a+19) /5 - 22+2=35
33a+209/5-22+2=35
33a+209/5-20=35
33a+209-100=175
33a+109=175
33a=175-109
33a= 66 /:2
a=2
B)5 •[a: 3570 (24 + 30:5)] - 23 = 27
5•(1/3570a • 30) - 23 = 27
5•(1/199a) - 23 =27
5• 1/199a - 23 =27
5a-2737=3213
5a=3213+2737
5a=5950 /:5
a=119