Răspuns :
Răspuns:
Explicație pas cu pas:
e.
[tex]-3\frac{1}{5} +(-2\frac{1}{6} +\frac{3}{2} )=[/tex]
[tex]=-\frac{16}{5} +(-\frac{13}{6} +\frac{9}{6} )=[/tex]
[tex]=-\frac{16}{5} +\frac{-13+9}{6}=[/tex]
[tex]=-\frac{16}{5} -\frac{4}{6}=[/tex]
[tex]=-\frac{96}{30} -\frac{20}{30}=[/tex]
[tex]=-\frac{116}{30} =[/tex]
[tex]=-3\frac{26}{30} =[/tex]
[tex]=-3\frac{13}{15}[/tex]
f.
[tex]\frac{8}{15} -(-1\frac{2}{3} +2\frac{1}{5} ) + \frac{7}{15} =[/tex]
[tex]=\frac{8}{15} -(-\frac{5}{3} +\frac{11}{5} ) + \frac{7}{15} =[/tex]
[tex]=\frac{8}{15} -(-\frac{25}{15} +\frac{33}{15} ) + \frac{7}{15} =[/tex]
[tex]=\frac{8}{15} -\frac{8}{15} + \frac{7}{15} =[/tex]
[tex]=\frac{7}{15}[/tex]
3.
a.
[tex]\frac{1}{3} +\frac{3}{4} +(\frac{2}{3} +\frac{5}{6} ) =[/tex]
[tex]= \frac{4}{12} +\frac{9}{12} +(\frac{4}{6} +\frac{5}{6} ) =[/tex]
[tex]= \frac{13}{12}+\frac{9}{6}=[/tex]
[tex]= \frac{13}{12}+\frac{18}{12}=[/tex]
[tex]= \frac{31}{12}[/tex]
b.
[tex]\frac{7}{15} -(\frac{3}{5} +\frac{4}{3} +\frac{1}{15} ) =[/tex]
[tex]=\frac{7}{15} -(\frac{9}{15} +\frac{20}{15} +\frac{1}{15} ) =[/tex]
[tex]=\frac{7}{15} -\frac{30}{15} =[/tex]
[tex]=-\frac{23}{15}[/tex]
c.
[tex]\frac{11}{9} -[\frac{3}{4} +(-\frac{5}{36} )]=[/tex]
[tex]=\frac{11}{9} -(\frac{3}{4} -\frac{5}{36} )=[/tex]
[tex]=\frac{11}{9} -(\frac{27}{36} -\frac{5}{36} )=[/tex]
[tex]=\frac{11}{9} -\frac{22}{36}=[/tex]
[tex]=\frac{11}{9} -\frac{11}{18}=[/tex]
[tex]=\frac{22}{18} -\frac{11}{18}=[/tex]
[tex]=\frac{11}{18}[/tex]
d.
[tex](-\frac{3}{14})+[(-\frac{1}{2}) +(+\frac{3}{7}) +(-\frac{5}{14} )] =[/tex]
[tex]-\frac{3}{14}+(-\frac{1}{2} +\frac{3}{7} -\frac{5}{14}) =[/tex]
[tex]-\frac{3}{14}+(-\frac{7}{14} +\frac{6}{14} -\frac{5}{14}) =[/tex]
[tex]-\frac{3}{14}+(-\frac{6}{14}) =[/tex]
[tex]-\frac{3}{14}-\frac{6}{14} =[/tex]
[tex]-\frac{9}{14}[/tex]
[tex]\it b)\ \dfrac{7}{15}-\Big(\dfrac{3}{5}+\dfrac{4}{3}+\dfrac{1}{15}\Big)=\dfrac{7}{15}-\dfrac{^{3)}3}{\ 5}-\dfrac{^{5)}4}{\ 3}-\dfrac{1}{15}=\dfrac{7-9-20-1}{15}=-\dfrac{23}{15}[/tex]
[tex]\it c)\ \dfrac{11}{9}-\Big[\dfrac{3}{4}+\Big(-\dfrac{5}{36}\Big)\Big]=\dfrac{^{4)}11}{\ 9}-\dfrac{^{9)}3}{\ 4}+\dfrac{5}{36}=\dfrac{44-27+5}{36}=\dfrac{\ 22^{(2}}{36}=\dfrac{11}{18}[/tex]
[tex]\it d)\ -\dfrac{3}{14}+\Big[\Big(-\dfrac{1}{2}\Big)+\Big(+\dfrac{3}{7}\Big)+\Big(-\dfrac{5}{14}\Big)\Big]=-\dfrac{3}{14}-\dfrac{^{7)}1}{\ 2}+\dfrac{^{2)}3}{\ 7}-\dfrac{5}{14}=\\ \\ \\ =\dfrac{-3-7+6-5}{14}=-\dfrac{9}{14}[/tex]