Denumiti urmatoarele substante:
A) Ca(OH) 2 ,
B) MgSO 4
C) K 2 S
D) H 3 PO 4

Si apoi calculati:
1. Masa molara
2. Raport de atomi
3. Raportul de masa
4. Compozitia procentuala

doar calculele cat mai repede va rog!!!

Răspuns :

Răspuns:

Explicație:

1.MCa(OH)2 =ACa+2AO+2AH=40+2*16+2*1=74

M MgSO4=AMg+AS+4AO=24 +32+4*16=120

M K2S=2AK+AS=2*39+32=110

MH3PO4=3AH+AP+4AO=3*1+31+4*16 =98

2. RaCa(OH)2=1:2:2

RaMgSO4=1:1:4

RaK2S=2:1

RaH3PO4=3:1:4

3 Rm Ca(OH)2 =ACa:2AO:2AH=40:2*16:2*1=

 Rm MgSO4=AMg:AS:4AO=24 :32:4*16=

Rm K2S=2AK:AS=2*39:32=

Rm H3PO4=3AH:AP:4AO=3*1:31:4*16=

4. Compozitia procentuala

74 g Ca(OH)2 .....40 gCa...32gO ....2gH

100g...................x..................y

120g MgSO4......24g Mg.....32g S....64 gO

100g......................x...........y

110g K2S.........78g K.....32g S

100g.......................x...        y

98g H3PO4.......3gH......31gP.......64 gO

100g .....................x..............y...............z

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