Răspuns:
Explicație:
1.MCa(OH)2 =ACa+2AO+2AH=40+2*16+2*1=74
M MgSO4=AMg+AS+4AO=24 +32+4*16=120
M K2S=2AK+AS=2*39+32=110
MH3PO4=3AH+AP+4AO=3*1+31+4*16 =98
2. RaCa(OH)2=1:2:2
RaMgSO4=1:1:4
RaK2S=2:1
RaH3PO4=3:1:4
3 Rm Ca(OH)2 =ACa:2AO:2AH=40:2*16:2*1=
Rm MgSO4=AMg:AS:4AO=24 :32:4*16=
Rm K2S=2AK:AS=2*39:32=
Rm H3PO4=3AH:AP:4AO=3*1:31:4*16=
4. Compozitia procentuala
74 g Ca(OH)2 .....40 gCa...32gO ....2gH
100g...................x..................y
120g MgSO4......24g Mg.....32g S....64 gO
100g......................x...........y
110g K2S.........78g K.....32g S
100g.......................x... y
98g H3PO4.......3gH......31gP.......64 gO
100g .....................x..............y...............z
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