Răspuns:
a.f:R-R f(x)=2x-4
f:[-2,3] g(x)=3x+1
f:[0,+∞) h(x)=x-1
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b)
f(x)=2x-4 Intersectia cu Ox f(x)=0
2x-4=0 2x=4
x=2
A(2,0)
f(0)=2·0-4=0-4= -4
B(0, -4)
Gf=AB dreapta
2x-4=y
2x=y+4
x=(y+4)/2 Ecuatia admite cel putin o solutie reala =>Imf=R
g(x)=3x+1
g(-2)=3*-2+1=-6+1= -5
A(-2,-5)
g(3)=3*3+1=9+1=10
B(3,10)
Gg=[AB] -segment
Im g=[-5,10]
h(x)=x-1
Intersectia cu Ox h(x)=0
h(x)=x-1=0 x=1
A(1,0)
Interectia cu Oy
h(0)=0-1= -1
B(0,-1)
Gh=(A,B semideapta
Im h=[-1,+∞)
Iti trimit imediat
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