Răspuns:
Explicație pas cu pas:
Într-un paralelogram diagonalele se injumatatesc
[tex]x_O=\frac{x_p+x_m}{2}= \frac{x_n+x_q}{2}=\frac{2+4}{2}=\frac{6}{2}=3\\\\\frac{x_n+x_q}{2}=\frac{5+x_q}{2}=3\\\\5+x_q=6\ =>\ x_q=1\\\\y_O=\frac{y_p+y_m}{2}= \frac{y_n+y_q}{2}=\frac{3+0}{2}=\frac{3}{2}\\\\\frac{y_Q+4}{2}=\frac{3}{2}\ =>\ y_Q+4=3 => y_Q=-1\\\\d_{MQ}: \frac{y_Q-y_M}{x_Q-x_M}=\frac{y-y_M}{x-x_M}\\\\d_{MQ}: \frac{-1-3}{1-2}=\frac{y-3}{x-2}\\\\d_{MQ}: \frac{-4}{-1}=4=\frac{y-3}{x-2}\\\\4x-8=y-3\ =>\ y-4x-3+8=0\\\\d_{MQ}: y-4x+5=0[/tex]
