2) unghiuri adiacente suplementare inseamna ca suma lor este 180°
4x+50+2x+10= 180
6x+60= 180
6x= 180-60,
6x= 120,
x= 20
3) ∆ ABC dreptunghic in A, BC ipotenuza.
BC^2= AB^2+AC^2
2500= 900+AC^2,
AC^2= 1600, AC= 40
AD inaltime
AD*BC= AB*AC (teorema inaltimii intr un ∆ dreptunghic)
AD*50=30*40
AD= 24 km
