Răspuns:
[tex]3x^{2} +5x+2=3x^{2} +3x+2x+2 =3x(x+1)+2(x+1)=(x+1)(3x+2)=0 ,x+1=0 x=-1 si 3x+2= 0 , x=-\frac{2}{3}[/tex]
A={-1,-[tex]\frac{2}{3}[/tex]}
(-1,[tex]\sqrt{2}[/tex]) rezulta -1 mai mare decat x mai mic decat rad2
