[tex]\displaystyle\bf\\m_a=\frac{7+8+7+7+8+10+6+8+8+9+8}{11}\\\\\\m_a=\frac{15+14+18+14+17+8}{11}\\\\\\m_a=\frac{29+32+25}{11}\\\\\\m_a=\frac{61+25}{11}\\\\\\m_a=\frac{86}{11}=7,81818181... = 7,(81)\\\\\\m_a\approx7,81\\\\Am~ luat~ primele~ 2~zecimale~fara~rotunjire~la~sutimi.\\Asa~ se~ procedeaza~ la~ calculul~ mediilor.[/tex]