Răspuns :

Luke48id

Salut!

[tex]\left \{ {{x+2y=3} \atop {5x-y=7}} \right. = \left \{ {{x=3-2y} \atop {5x-y=7}} \right. = \left \{ {{x=3-2y} \atop {5(3-2y)-y=-7=2}} \right. = \left \{ {{x=3-2y} \atop {15-11y=-7}} \right. = \left \{ {{x=3-2y} \atop {-11y=-22}} \right. = \left \{ {{x=3-2y} \atop {y=2} \right. = \left \{ {{x=3-2\cdot 2} \atop {y=2}} \right. = \left \{ {{x=-1} \atop {y=2}} \right.[/tex]

*Am folosit metoda substitutiei.

-Luke48

Slavitescudoraid

Aplic metoda substitutiei

x+2y= 3

5x-y = -7

x = 3-2y

5(3-2y)-y = -7

x = 3-2y

15-10y -y = -7

x = 3-2y

-11y= -22

x = 3-2*2

y= 2

x = -1

y =2

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