Răspuns :

Cristinatibulcaid
Q=mcΔT⇒m=Q/cΔT
c=4180J/KgK caldura specifica a apei
m= 2 kg, 
ρ=m/V⇒V=m/ρ=2/1000=0.002 [tex] m^{3} [/tex]

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