a)
[tex] \frac{3 x- 2}{ {x}^{2} } = \frac{3 - 2}{1} = \frac{1}{1} = 1[/tex]
b)
[tex] \frac{x + 1}{ {x}^{2} + x + 1 } = \frac{1 + 1}{1 + 1 + 1} = \frac{2}{3} [/tex]
c)
[tex] \frac{x - 2}{ {x}^{2} - 2x - 2 } = \frac{1 - 2}{1 - 2 - 2} = \frac{ - 1}{ - 3} = \frac{1}{3} [/tex]
Coroana?