[tex] {x}^{2} - 15 + 50 = 0[/tex]
a=1
b=15
c=50
∆=b²-4ac. formula
∆=15²-4x1x50
∆=225-200
∆=25
x1= - b+✓∆ / 2a. formula
x1=-15+5/2
x1=20/2
x1=10
x2=-b-✓∆/2a. formula
x2=-15-5/2
x2=-20/2
x2=-10
x={-10;10}
Bafta!!!
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