Răspuns :
x,y d.p. 2,3 => x/2, y/3 =k
x/2 = k => x= 2k
y/3 = k => y= 3k
2k+3k = 5k
x/2 × 5k => x= 5x/2
y/3 × 5k => y= 5x/3
5x/2 + 5x/3
15x/6 + 10x/3
15x +10x - 12= 13
x,y d.p. 2,3 => x/2, y/3 =k
x/2 = k => x= 2k
y/3 = k => y= 3k
2k+3k = 5k
x/2 × 5k => x= 5x/2
y/3 × 5k => y= 5x/3
5x/2 + 5x/3
15x/6 + 10x/3
15x +10x - 12= 13