Răspuns :

Mihaiimbriscaid

Răspuns:

MFe=56g/mol

m=5,8×56=324,8gFe

MFeCl3=56+3×35,5=162,5g/mol

2×56g.....................2×162,5g

2Fe +3Cl2 => 2FeCl3

324,5g.......................xg

x=324,5×2×162,5/2×56= calculează

Răspuns:

2Fe+3Cl2=2FeCl3

2moli            2moli

5,8moli       x

x=5,8 moli FeCl3

MFeCl3=AFe+3ACl=56+3*35,5=162,5

m=n*M=5,8 moli*162,5 g/mol=942,5 g

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