Răspuns :

Adrianbuf18id

x/y=2/3 => 2y=3x => y=3x/2

=> (6x+y)/(x+3y)=(6x+3x/2)/(x+9x/2)

Aducem la acelasi numitor in paranteze si obtinem:

(12x/2+3x/2)/(2x/2+9x/2)=(15x/2)/(11x/2)

sa imparti la o fractie inseamna sa inmultesti cu inversa acesteia deci:

(15x/2)/(11x/2)=(15x/2)•(2/11x)=(2•15x)/(2•11x)=15/11

MFMid

[tex]\frac{x}{y}[/tex] =2/3

x/2=y/3=k

x=2k

y=3k

(6·2k+3k)/(2k+3·3k)=15k/11k=15/11

ID Alte intrebari