1/(√3+1)+1/(√3-1)=
=(√3-1)/[(√3)²-1]+(√3+1)/[(√3)²-1]=
=(√3-1)/(3-1)+(√3+1)/(3-1)=
=(√3-1)/2+(√3+1)/2=
=(√3-1+√3+1)/2=
=2/2=1