Explicație pas cu pas:
a) 2×{92+8×[1004+4×(8:2×2-4×2:2)]}
2×{92+8×[1004+4×(8-4×1)]}
2×{92+8×[1004+4×(8-4)]}
2×{92+8×[1004+4×4]}
2×{92+8×[1004+16]}
2×{92+8×1020]
2×{92+8160}
2×8252
16504
c) 8-7:{6-5:[4-3:(2-2:2)]}
8-7:{6-5:[4-3:(2-1)]}
8-7:{6-5:[4-3:1]}
8-7:{6-5:[4-3]}
8-7:{6-5:1}
8-7:{6-5}
8-7÷1
8-7
1
b) (2019×2018-2018×2017)×2019⁰:1²⁰¹⁸
2018×(2019-2017)×1:1
(orice numar la puterea 0 da 1,iar 1 ridicat la orice putere tot 1 e)
2018×(2019-2017)÷1
2018×(2019-2017)
2018×2
4036