Răspuns :

Miky93id
ΔABC,mas<A=90
sin<B=30= 1/2
sin<B=AC/BC    1/2  =AC/6  AC=6/2=3
AB²=BC²-AC²=6²-3²=36-9=27  ⇒AB=3√3

A=c1*c2/2=  AC*AB/2=  3*3√3/2=  9√3/2
Razvanw0wid
[tex]BC=6\; , \; m(\hat{B})=30 \Rightarrow AC=3\\ AB=\sqrt{BC^2-AC^2}=\sqrt{36-9}=\sqrt{25}=5\\ A_{\Delta}=\dfrac{c_1\cdot c_2}{2}=\dfrac{AB\cdot AC}{2}=\dfrac{5 \cdot 3}{2}=7,5 \; cm^2[/tex]

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