Răspuns:
Explicație:
CuSO4 .5H2O
M= 64 + 32 +4.16 + 5 . 18
=250 -------> 250g/moli
250 g CuSO4 .5H2O---------------------90 g H2O
100 g----------------------------------------------------x
x= 100 .90 : 250 =36%H2O
FeSO4 . 7H2O
M= 56 + 32 +4.16 + 7.18=278 ------->278g/moli
278 g FeSO4 . 7 H2O----------126 g H2O
100 g--------------------------------------y
y= 100 126 : 278= 45,32%H2O
