NU se aplica regula de trei simpla....!!!
ms1 = 200 g, c1% = 30%
ms2 = ms1 + a, unde a = masa de zahar adaugata
stim ca c% = mdx100/ms
=> md1 = ms1xc1%/100
= 200x30/100 = 60 g zahar
md2 = md1+a
=> 45 = md2x100/ms2
=> 45 = (md1+a)100/(ms1+a)
=> 45(200+a) = (60+a)100
=> a = 3000/55 = 54,55 g zahar adaugat
facem proba:
ms2 = 254,55 g, md2 = 114,55 g
=> c2% = 114,55x100/254,55 = 45%......... deci verifica ce am rezolvat mai sus