Răspuns :
Salutare !!!
Pentru a fi mai usoare calcule vom descompune numerele de sub radical
32 = 2⁵
1024 = 2¹⁰ = 32²
135 = 3³ × 5
1225 = 5² × 7² = 35²
2025 = 3⁴ × 5² = 45²
[tex]\bf\dfrac{\sqrt{32+\sqrt{1024}}}{\sqrt{135-\sqrt{1225}}}=\dfrac{2x}{\sqrt{270-\sqrt{2025}}}[/tex]
[tex]\bf\dfrac{\sqrt{32+32}}{\sqrt{135-35}}=\dfrac{2x}{\sqrt{270-45}}[/tex]
[tex]\bf\dfrac{\sqrt{64}}{\sqrt{100}}=\dfrac{2x}{\sqrt{225}}[/tex]
[tex]\bf\dfrac{\sqrt{8^{2} }}{\sqrt{10^{2} }}=\dfrac{2x}{\sqrt{15^{2} }}[/tex]
[tex]\bf\dfrac{{8}}{10}}=\dfrac{2x}{15}}[/tex]
[tex]\bf\dfrac{{\not8}}{\not10}}=\dfrac{2x}{15}}[/tex]
[tex]\bf\dfrac{{4}}{5}}=\dfrac{2x}{15}}[/tex]
[tex]\bf5\cdot2x=4\cdot15[/tex]
[tex]\bf 10x=60[/tex]
[tex]\bf x=60:10[/tex]
[tex]\boxed{\bf x=6}[/tex]
[tex]\frac{\sqrt{32+\sqrt{1024}}}{\sqrt{135-\sqrt{1225}}} =\frac{2x}{\sqrt{270-\sqrt{2025}}}[/tex]
[tex]\sqrt{1024}=32\\\sqrt{1225}=35\\\sqrt{2025}=45[/tex]
[tex]\frac{\sqrt{32+32}}{\sqrt{135-35}} =\frac{2x}{\sqrt{270-45}}[/tex]
[tex]\frac{\sqrt{64}}{\sqrt{100}} =\frac{2x}{\sqrt{225}}[/tex]
[tex]\sqrt{64}=8\\\sqrt{100}=10\\\sqrt{225}=15[/tex]
[tex]\frac{8}{10} =\frac{2x}{15}\\\\10*2x=8*15\\\\20x= 120\\\\x=120:20\\\\x=6[/tex]