Răspuns:
Explicație pas cu pas:
[tex]a-b = 3\frac{1}{5} => a-b = \frac{3*5+1}{5} => a-b = \frac{16}{5} => 5*(a-b) = 16=>5a-5b = 16 \\\\a= 3b \: \: \:inlocuim \: \: \:in \: \: \:prima \: \: \:relatie\\\\5 * 3b - 5b = 16\\\\ 15b -5b=16\\\\10b = 16\\\\b = \frac{16}{10}\\\\ \boxed {b = \frac{8}{5}}\\\\ a = \frac{8}{5} *3\\\\ \boxed{a = \frac{24}{5}}\\\\Verificare: \frac{24}{5} - \frac{8}{5} = \frac{16}{5}[/tex]
