1.
C2H6 + 7/2O2 --> 2CO2 + 3H2O
C3H8 + 5O2 --> 3CO2 + 4H2O
2.
nr.moli = 6000/22,4 = 267,86 moli amestec etan + propan
a + 2a = 267,86 => a = 89,28
89,28 moli n1 moli
C2H6 + 7/2O2 --> 2CO2 + 3H2O
1 2
178,57 moli n2 moli
C3H8 + 5O2 --> 3CO2 + 4H2O
1 3
=> n1 = 178,56 moli CO2 rezultati la arderea C2H6
=> n2 = 535,71 moli CO2 rezultati la arderea C3H8
=> nr.moli.totali.CO2 = n1+n2 = 714,27 moli
=> V.total.CO2 = 714,27x22,4 = 1600 L CO2
3.
notam alchina (A) = CnH2n-2
6,75 g 0,25 moli
CnH2n-2 + 2Br2 --> CnH2nBr4
miu 2
=> miu = 6,75x2/0,25 = 54 g/mol
=> 14n-2 = 54 => n = 4
alchina C4 cu 2 at de C => H3C-C≡C-CH3 , 2-butina
4.
H3C-C≡CH + H2O --HgSO4/H2SO4-->
[H3C-C=C-OH] <==---> H3C-CO-CH3
enol instabil
5.
obtinerea de mase plastice de tip PVC
