Va rog frumos ajutați-mă si pe mine!!! Calculati in doua moduri sumele,folosind modelul urmator
-1+(+2)+(-3)+(+4)=+1+(-3)+(+4)=-2+(+4)=+2 sau -1+(+2)+(-3)+(+4)=-1+(-3)+(+2)+(+4)=(-4)+(+6)=+2

a) (-4)+(+6)+(-8)+(+3)
b) (+5)+(-7)+(+10)+(-6)
c) (-2)+(-22)+(+30)+(-9)
d) (+13)+(+77)+(-40)+(-60)​

Răspuns :

Explicație pas cu pas:

Buna!

[tex]\large\bf a)~~ (-4)+(+6)+(-8)+(+3) =[/tex]

[tex]\large\bf - 4 + 6 - 8 + 3 =[/tex]

[tex]\large\bf 2 - 8 + 3 =[/tex]

[tex]\large\bf - 6 + 3 =[/tex]

[tex]\color{teal}\Large\boxed{\bf-3}[/tex]

[tex]\it~~~[/tex]

[tex]\large\bf b)~~ (+5)+(-7)+(+10)+(-6) =[/tex]

[tex]\large\bf 5 - 7 + 10 - 6 =[/tex]

[tex]\large\bf - 2 + 10 - 6 =[/tex]

[tex]\large\bf 8 - 6 =[/tex]

[tex]\color{red}\Large\boxed{\large\bf 2}[/tex]

[tex]\it~~~[/tex]

[tex]\large\bf c)~~ (-2)+(-22)+(+30)+(-9) =[/tex]

[tex]\large\bf - 2 - 22 + 30 - 9 =[/tex]

[tex]\large\bf - 24 + 30 - 9 =[/tex]

[tex]\large\bf 6 - 9 =[/tex]

[tex]\color{purple}\Large\boxed{\bf -3}[/tex]

[tex]\it~~[/tex]

[tex]\large \bf d)~~ (+13)+(+77)+(-40)+(-60) =[/tex]

[tex]\large \bf 13 + 77 - 40 - 60 =[/tex]

[tex]\large \bf 90 - 40 - 60 =[/tex]

[tex]\large \bf 50 - 60 =[/tex]

[tex]\color{blueviolet}\Large \boxed{\bf - 10}[/tex]

==pav38==