Răspuns:
A)
[tex]h = \frac{l \sqrt{3} }{2} \\ \\ h = \frac{8 \sqrt{3} }{2} \\ \\ h = 4 \sqrt{3} [/tex]
B)
[tex]perimetru \: patrat = 4l \\ \\48 = 4l = > l = 48 \div 4 = > l = 12 \\ \\ diagonala \: patrat = l \sqrt{2} \\ \\ diagonala \: patrat = 12 \sqrt{2} [/tex]