Răspuns:
a) Ab= πR²= 6*6π=36 π G=h l=2R
Al=2πR*G= 2*6*8π=96 π
At=Al+Ab=96+36=132 π
V=πR²G= 36*8π=288π d= [tex]\sqrt{h^{2} +l^{2} }[/tex] =[tex]\sqrt{64+144}[/tex]= [tex]\sqrt{208}[/tex]= 4[tex]\sqrt{13}[/tex]
b) Ab= πR²= 100π l=2R=20
V=πR²G => G= V/πR² = 600π/π100= 6 cm G=h=6
Al=2πR*G= 2*6*10π=120 π
At= Al+Ab=120+100=220 π
d²= l²+h²=400+36=436 d=[tex]\sqrt{436}[/tex]=2[tex]\sqrt{109}[/tex]
c) Ab=πR²=16π l=2R= 2*4=8
Al=2πR*G => G= Al/2πR= 80π/ 2π4=80/8=10 G=h=10
At= Al+Ab=16+80=96 π
V= πR²G = 16*10π=160 π
d²= l²+h²= 64+100=164 d= [tex]\sqrt{164}[/tex]= 2[tex]\sqrt{41}[/tex]
d)V= πR²G => R²= 63π/7π=9 R=3 G=h=7
Ab= πR²= 9π l=2*3=6
Al=2πR*G = 2*3*7π=42 π
At= Al+Ab=9+42=51 π
d²= l²+h² = 36+49=85 d= [tex]\sqrt{85}[/tex]
e) Al=2πR*G R*G=600π/2π=300
V= πR²G 4500π= πR*G*R=> R= 4500π/πR*G=4500/300=15
R=15 G= 300:15=20 G=h=20 l=2R=2*15=30
Ab= πR²= 225π
At=Ab+Al= 225+600=825 π
d²=l²+h²=900+400=1300 d=[tex]\sqrt{1300}[/tex] =10[tex]\sqrt{13}[/tex]
restul dupa model
