Răspuns:
Explicație:
masa NH4Cl= 21,4 g
react. cu Ca(OH)2
VNH3 =?
21,4g xg
2NH4Cl + Ca(OH)2 = CaCl2 + 2NH3 +2 H2O
2 .53,5g 2 .17g
x=21,4 . 2 .17 : 2 .53,5=6,8 g NH3
n= 6,8g : 17g/moli=0,4 moli NH3
VNH3= 0,4moli . 22,4L/moli= 8,96 L
MNH4Cl=14 +4+35,5-53,5------->53,5g/moli
MNH3=14 +3=17------> 17g/moli