Răspuns :
N=13+2(1+2+...+12) ?
1+2++..+12=
12*13/2=
6*13=78
N=13+2*78
N=13+156
N=169
=====================
A+B+C=75
2B-C=13
C=9
2B-9=13
2B=13+9
2B=22
B=11
A+11+9=75
A+20=75
A=75-20
A=55
1+2++..+12=
12*13/2=
6*13=78
N=13+2*78
N=13+156
N=169
=====================
A+B+C=75
2B-C=13
C=9
2B-9=13
2B=13+9
2B=22
B=11
A+11+9=75
A+20=75
A=75-20
A=55
Prima problema:
13+2(1+2+....+12)=13+2·12·13:2
=13(1+12)
=13·13
=169
1+2+3+....+12=12·13:2 (SUMA GAUS)
A doua problema:
A+B+C=75
2B-C=13
C=9 REZULTA 2B-9=13 2B=22 B=11
A=75-11-9
A=55
13+2(1+2+....+12)=13+2·12·13:2
=13(1+12)
=13·13
=169
1+2+3+....+12=12·13:2 (SUMA GAUS)
A doua problema:
A+B+C=75
2B-C=13
C=9 REZULTA 2B-9=13 2B=22 B=11
A=75-11-9
A=55