Răspuns :
f(1)=1 =>x=1=>p1+q=1=> p+q=1
f(2)=-1=>x=2=>p2+q=-1=>2p+q=-1
p+q=1 /(-1)
2p+q=-1
-p-q=-1
2p+q=-1
p /=-2 ∈ R
p+q=1=>-2+q=1=>q=1+2=>q=3∈ R
f(2)=-1=>x=2=>p2+q=-1=>2p+q=-1
p+q=1 /(-1)
2p+q=-1
-p-q=-1
2p+q=-1
p /=-2 ∈ R
p+q=1=>-2+q=1=>q=1+2=>q=3∈ R