Răspuns :
a, b dp cu 5,3
a/5=b/3=k
a=5k
b=3k
a:b=1 rest 14
a=b+14
5k=3k+14
5k-3k=14
2k=14
k=7
a=35
b=21
p% din b= a
p% din 21=35
p/100=35/21
p=100*35/21
p=100*5/3
p=166,6%
a/5=b/3=k
a=5k
b=3k
a:b=1 rest 14
a=b+14
5k=3k+14
5k-3k=14
2k=14
k=7
a=35
b=21
p% din b= a
p% din 21=35
p/100=35/21
p=100*35/21
p=100*5/3
p=166,6%
a/5=b/3=k
a=5k
b=3k
a:b=1 rest 14
a=b+14
5k=3k+14
5k-3k=14
2k=14
k=7
a=35
b=21
p% din b= a
p% din 21=35
p/100=35:21
p=100x35:21
p=100x5:3
p=166,6%
BAfta
a=5k
b=3k
a:b=1 rest 14
a=b+14
5k=3k+14
5k-3k=14
2k=14
k=7
a=35
b=21
p% din b= a
p% din 21=35
p/100=35:21
p=100x35:21
p=100x5:3
p=166,6%
BAfta