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REZOLVATI IN RINECUATIA
a) 3x+17<x=13
b)6x-2>7x+8
c)x+4<12+9x
d)7+6x<2(5x-8)
e)4x-11<x+13
f)8x+3<9x-2
g)6-4x>7-6x
h)10x+9>-3(2-5x)
i)3(2x-1)+5<2x+7

Răspuns :

Cristinatibulcaid
a) 3x+17<x-13
2x<-17-13
2x<,-30
x<-15, x∈(- infinit, -15)
b) 6x-2>7x+8
6x-7x>8+2
-x>10
x<-10, x∈(-infinit, 10)
c. x+4<12+9x
-8x<8
x>-1, x∈(-1, + infinit)
d. 7+6x<2(5x-8)
7+6x<10x-16
-4x<-23
x>23/4, x∈(23/4, + infinit)

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