⇒{√3x+2x+3√2y=2x-12⇒ {√3x+2x-2x+3√2y=-12⇒ {√3x+3√2y=-12 ·(-2)⇒
{2√3x+√2y+3y=3y+6⇒ {2√3x+√2y+3y-3y=6⇒ {2√3x+√2y=6
{-2√3x-6√2y=24
{2√3x+√2y=6⇒ se reduce x⇒ -6√2y+√2y=24+6⇒ -5√2y=30 ·(-1)⇒
y=-30/5√2 simplificam⇒y=-6/√2=-6√2/2⇒y=-3√2
din relatia √3x+3√2y=-12 inlocuim x=(-12-3√2y)/√3
x=(-12-3·-3√2)/√3=(-12+9√2)/√3=(-12√3+9√6)/3=3(-4√3+3√6)/3
x=-4√3+3√6
