2√6( 3/ √2 - 2/ √3) rationalizam
2√6(3√2/2 - 2√3/3) aducem la acelasi numitor in paranteza
2√6 * (9√2-4√3)/6 = √6( 9√2 -4√3)/3= (9√12 -4√18)/3= (18√3- 12√2)/3
2(3√3-2√2)= 6√3- 4√2
(18√3 -12√2)/3 -(6√3-4√2) aducem la acelasi numitor
18√3-12√2 -18√3 + 12√2 se simplifica si ne da 0
