Răspuns:
[tex]g)7 \sqrt{3} - 3(2 + \sqrt{3} ) + 1 = \\ 7 \sqrt{3} - 6 - 3 \sqrt{3} + 1 = \\ = 4 \ \sqrt{3} - 5[/tex]
[tex]b)4 \sqrt{3} ( - \frac{1}{2} \sqrt{2}) = - 2 \sqrt{6} [/tex]
[tex]f) \sqrt{6} \times \sqrt{2} + 2 \sqrt{12} - 3 + \sqrt{12} = \\ \sqrt{12} + 2 \sqrt{12} + \sqrt{12} - 3 = 4 \sqrt{12 } - 3[/tex]
[tex]h)4 - 2( \sqrt{3} + 1) + 5 \sqrt{3} = \\ 4 - 2 \sqrt{3} - 2 + 5 \sqrt{3} = 2 + 3 \sqrt{3} [/tex]
[tex]i)4( \sqrt{3} + 2) - 2 \sqrt{3} - 8 = \\ 4 \sqrt{3} + 8 - 2 \sqrt{3} - 8 = 2 \sqrt{3} [/tex]
[tex]j)10 \sqrt{5} - 5( \sqrt{5} + 2) - 4 + 3 \sqrt{5 } = \\ 10 \sqrt{5 } - 5 \sqrt{5} - 10 - 4 + 3 \sqrt{5} = \\ = 8 \sqrt{3} - 14[/tex]
[tex]k)3( \sqrt{6} + 1) - 2(1 + \sqrt{6} ) = \\ 3 \sqrt{6} + 3 - 2 - 2 \sqrt{6} = \sqrt{6 } + 1[/tex]
[tex]l)3( \sqrt{7} - 2 ) + 2(3 - \sqrt{7} ) = \\ 3 \sqrt{7 } - 6 + 6 - 2 \sqrt{7} = \sqrt{7} [/tex]
