Răspuns:
Reactia de combinare reprezinta procesul chimic de formare a unui singur produs de reactie o substanta compusa.
1. 2H2 + O2 → 2H2O - apă
2. H2 +Cl2 → 2HCl - acid clorhidric
3. H2 +3N2 → 2NH3 - amoniac
4. NH3 + HCl → NH4Cl - clorura de amoniu
5. 2Mg + O2 → 2MgO - oxid de magneziu
6. MgO + H2O → Mg(OH)2 - hidroxid de magneziu
7. 2Fe + 3Cl2 → 2FeCl3 clorura de fier III
8. Mg + Cl2 → MgCl2 cloruar de magneziu
2.
MH2=2x1=2g/mol
MCl2=2x35,5=71g/mol
m=nxM=7x71=497gCl2
2g........71g
H2 + Cl2 → 2HCl
xg.........497g
x=2x497/71=calculeaza
3.
MH2=2x1=2g/mol
MNH3=14+3x1=17g/mol
3x2g.............2x17g
3H2 + N2 → 2NH3
24g....................xg
x=24x2x17/3x2=calculeaza
4.
MNH3=14+3x1=17g/mol
17g NH3..............3gH
100gNH3..............x%H
x=100x3/17=calculeaza
MH2O=2x1+16=18g/mol
18g H2O.............2gH
100gH2O............y%H
y=100x2/18=calculeaza
MCH4=12+4x1=16g/mol
16gCH4.............4gH
100gCH4...........z%H
z=100x4/16=calculeaza
5.
MCl2=2x35,5=71g/mol
MAlCl3=27+3x35,5= 133,5g/mol
m=nxM=9x71=639gCl
3x71g....2x133,5g
2Al + 3Cl2 → 2AlCl3
639g........xg
x=639x2x1335,5/3x71=calculeaza
calculam in moli
3moli.....2moli
2Al + 3Cl2 → 2AlCl3
9moli.....ymoli
y=9x2/3=calculeaza
Explicație:
a=O oxigen
b= Cl -clor
d= N azot
e= NH4Cl - clorura de amoniu
f= MgO - oxid de magneziu
g= Mg(OH)2 - hidroxid de magneziu
h=FeCl3 clorura de fier III
i= MgCl2 cloruar de magneziu
