[tex]\it \bf 5.\ \it a)\ =(-\dfrac{3}{7})\cdot\Big(\dfrac{\ \ 15^{(3}}{9}+\dfrac{2}{3}\Big)=(-\dfrac{3}{7})\cdot\Big(\dfrac{5}{3}+\dfrac{2}{3}\Big)=-\dfrac{\not3}{\not7}\cdot\dfrac{\not7}{\not3}=-1\\ \\ \\ b)\ =2\dfrac{1}{37}\cdot\Big(\dfrac{11}{3}-\dfrac{\ \ 12^{(2}}{10}\Big)=\dfrac{75}{37}\cdot\Big(\dfrac{^{5)}11}{3}-\dfrac{^{3)}6}{5}\Big)=\dfrac{75}{\not37}\cdot\dfrac{\not37}{15}=\dfrac{75}{15}=5[/tex]
6.
[tex]\it \dfrac{3}{5}+1.25=0,6+1,25=1,85\ \ell\ (con\c{\it t}ine\ al \ doilea\ urcior)\\ \\ 1,85-0,5=1,35\ \ell\ (con\c{\it t}ine\ al \ treilea\ urcior)\\ \\ 1,35-0,6=0,75\ \ell\ (con\c{\it t}ine\ mai\ mult\ al\ treilea\ urcior\ dec\hat at\ primul)[/tex]
