x-primul frate
y-al doilea frate
z-al treilea frate
x+y+z=3960.
x=1/2·y.
z=(y+180)·3
1/2·y+y+(y+180)·3=3960.
1/2·y+y+3y+540=3960
1/2·y+y+3y=3420
1/2·y+4y=3420 |·2
y+8y=6840
9y=6840⇒y=6840/3=760⇒x=760/2=380.
y=760⇒z=(760+180)·3=940·3=2820.
RASPUNS: primul frate(x)=380;
al doilea frate(y)=760;
al treilea frate(z)=2820.