[tex]\it a)\ \ =-8+\dfrac{1}{9}-4\cdot1=-12+\dfrac{1}{9}=-\dfrac{107}{9}\\ \\ \\ b)\ \ =4-12\sqrt5+45+4\sqrt5=49-8\sqrt5\\ \\ \\ c)\ \ =-5-6+4=-7[/tex]
