Răspuns:
a) √3
b) 4√3 - 5√2
c) [tex]\frac{8\sqrt{2} }{3}[/tex]
Explicație pas cu pas:
a)
[tex]\frac{6}{\sqrt{3} } + 2\sqrt{3} - \sqrt{27}[/tex]
[tex]= \frac{6\sqrt{3} }{3} + 2\sqrt{3} - 3\sqrt{3}[/tex]
[tex]= 2\sqrt{3} - \sqrt{3}[/tex]
[tex]= \sqrt{3}[/tex]
b)
[tex]\frac{10}{\sqrt{2} } + \frac{12\sqrt{2} }{\sqrt{6} } - 2\sqrt{50}[/tex]
[tex]= \frac{10\sqrt{2} }{2} + \frac{12\sqrt{12} }{6} - 2*5\sqrt{2}[/tex]
[tex]= 5\sqrt{2} + 2*2\sqrt{3} - 10\sqrt{2}[/tex]
[tex]= 4\sqrt{3} - 5\sqrt{2}[/tex]
c)
[tex]\frac{5}{\sqrt{2} } + \frac{7}{3\sqrt{2} } - \frac{2\sqrt{3} }{\sqrt{6} }[/tex]
[tex]= \frac{5}{\sqrt{2} } + \frac{7}{3\sqrt{2} } - \frac{2}{\sqrt{2} }[/tex]
[tex]= \frac{5*3 + 7 - 2*3}{3\sqrt{2} } = \frac{15 + 7 - 6}{3\sqrt{2} } = \frac{16}{3\sqrt{2} } = \frac{16\sqrt{2} }{6} = \frac{8\sqrt{2} }{3}[/tex]
