[tex]\it -1<x+5\leq4|_{-4} \Rightarrow -5<x\leq1 \Rightarrow A=(-5,\ \ 1]\\ \\ |x+\dfrac{3}{5}|<2 \Rightarrow -2<x+\dfrac{3}{5}<2\Big|_{-\frac{3}{5}} \Rightarrow -\dfrac{13}{5}<x<\dfrac{7}{5} \Rightarrow B=\Big(-\dfrac{13}{5},\ \ \dfrac{7}{5}\Big)[/tex]
[tex]\it A\cap B=\Big(-\dfrac{13}{5},\ \ \Big1][/tex]
