Răspuns:
Bună,
[tex] \frac{2 - \sqrt{3} }{ \sqrt{3} } = \\ \frac{ \sqrt{3} (2 - \sqrt{3)} }{ \sqrt{3} \times \sqrt{3} } = \\ \frac{2 \sqrt{3} - 3 }{3} [/tex]
[tex] \frac{1 - \sqrt{5} }{3 \sqrt{5} } = \\ \frac{ \sqrt{5}(1 - \sqrt{5}) }{3 \times 5} = \\ \frac{ \sqrt{5} - 5}{15} [/tex]
[tex] \frac{ \sqrt{22} - \sqrt{33} }{2 \sqrt{11} } = \\ \frac{ \sqrt{11}( \sqrt{22} - \sqrt{33} ) }{2 \sqrt{11} \times \sqrt{11} } = \\ \frac{ \sqrt{242} - \sqrt{363} }{2 \times 11} = \\ \frac{11 \sqrt{2} - 11 \sqrt{3} }{22} = \\ \frac{11( \sqrt{2 }- \sqrt{3}) }{22} = \\ \frac{ \sqrt{2} - \sqrt{3} }{2} [/tex]
[tex] \frac{ \sqrt{80} - \sqrt{45} }{ \sqrt{75} } = \\ \frac{4 \sqrt{5} - 3 \sqrt{5} }{5 \sqrt{3} } = \\ \frac{ \sqrt{5} }{5 \sqrt{3} } = \\ \frac{ \sqrt{5 } \times \sqrt{3} }{5 \times \sqrt{3} \times \sqrt{3} } = \\ \frac{ \sqrt{15} }{15} [/tex]
Sper că te-am ajutat
