Ma puteti ajuta la 4,5,6?am nevoie urgent

4)
(25+15):5=40:5=8
(25:5)+(15:5)=5+3=8
(45+39):3=84:3=28
(45:3)+(39:3)=15+13=28
(81-27):9= 54:9=6
(81:9)-(27:9)=9-3=6
(16+28):4=44:4=11
(16:4)+(28:4)=4+7=11
(44+48):4=92:4=23
(44:4)+(48:4)= 11+12=23
(45-20):5=25:5=5
(45:5)-(20:5)=9-4=5
(78-46):2=32:2=16
(78:2)-(46:2)=39-23=16
(96-48):3= 48:3=16
(96:3)-(48:3)= 32-16=16
5)
(11+4):3=15:3=5 => procedeul corect de rezolvare
(11:3)+(4:3)=> 11:3 și 4:3 ne da cu virgula
6)
(21+14+35):7=> (21:7)+(14:7)+(35:7)=3+2+5=10
(16+20+32):4=>(16:4)+(20:4)+(32:4)=4+5+6=17
(35+45+30):5=>(35:5)+(45:5)+(30:5)=7+9+6=22

Sper sa te ajute :)

Alessiasulic92id Alessiasulic92id · Answer 2

Răspuns:

4 Efectuează calculele, folosind ambele procedee de lucru:

(25+15):5=40:5=8

(16+28):4=44:4=11

(45+39):4=84:4=21

(44+48):4=92:4=23

(81-27):9=54:9=6

(45-20):5=25:5=5

(78-46):2=32:2=16

(96-48) :3=58:3=19

5.- Efectuează, in doua moduri exercițiul (11+4):3

- eu pot efectua intrun singur mod.

(11+4):3=15:3=5

6.calculeaza,impartind fiecare dintre termen al sumei la impartitor:

A)(21+14+35):7=70:7=10

B)(16+20+32):4=68:4=17

C) (35+45+30):5=110=22