Răspuns :

Diamantdelaceliniid

Răspuns:

Bună,

[tex] \frac{ 5 }{2 \sqrt{2} } + \frac{4}{3 \sqrt{2} } + \frac{1}{6 \sqrt{2 } } = \\ \frac{5 \sqrt{2} }{2 \times 2} + \frac{4 \sqrt{2} }{3 \times 2} + \frac{ \sqrt{2} }{6 \times 2} = \\ \frac{5 \sqrt{2} }{4} + \frac{4 \sqrt{2} }{6} + \frac{ \sqrt{2} }{12} = \\ \frac{15 \sqrt{2} }{12} + \frac{8 \sqrt{2} }{12} + \frac{ \sqrt{2} }{12 = } \\ \frac{24 \sqrt{2} }{12} = \\ 2 \sqrt{2} [/tex]

Sper că te-am ajutat

Biancabutnariu2265id

[tex] \frac{5}{2 \sqrt{2} } + \frac{4}{3 \sqrt{2} } + \frac{1}{6 \sqrt{2} } = [/tex]

[tex] \frac{5 \sqrt{2} }{4} + \frac{4}{3 \sqrt{2} } + \frac{1}{6 \sqrt{2} } = [/tex]

[tex] \frac{5 \sqrt{2} }{4} + \frac{2 \sqrt{2} }{3} + \frac{1}{6 \sqrt{2} } = [/tex]

[tex] \frac{5 \sqrt{2} }{4} + \frac{2 \sqrt{2} }{3} + \frac{ \sqrt{2} }{12} = [/tex]

[tex] \frac{3 \times 5 \sqrt{2} }{3 \times 4} + \frac{4 \times 2 \sqrt{2} }{4 \times 3} + \frac{ \sqrt{2} }{ {12} } = [/tex]

[tex] \frac{15 \sqrt{2} }{12} + \frac{8 \sqrt{2} }{12} + \frac{ \sqrt{2} }{12} = [/tex]

[tex] \frac{15 \sqrt{2} + 8 \sqrt{2} + \sqrt{2} }{12} = [/tex]

[tex] \frac{24 \sqrt{2} }{12} = [/tex]

[tex] = 2 \sqrt{2} [/tex]

Rezultatul este 2√2

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